Simple skill problem

Hi,

I have some basic problem with SKILL

I have 3 lists, each equally long containing values. Now I want to print
them out. I tried

(foreach crossed rx_cross
(printf "%L %L %L\n" crossed (car tx_cross) (clk_cross))

but because car is not destructive, I always get the first element of
tx_cross list and clk_cross list. I looked into the manual and tried to
find some examples solving this kind of problem, but my problem is that
I simply don't understand SKILL good enough to find a fitting command.

 

Would (mapc (lambda (a b c) (printf "%s %s %s\n" a b c)) crossed
(car tx_cross) (clk_cross)) be what you are looking for?

 

Ahh, this is one of my favorite tricks:

foreach can iterate through multiple lists at the same time, even lists
of different lengths. For example:

l1 = list(1 2)
l2 = list(5 6 7)
l3 = list(9 10 11 12)

RC = foreach((x y z) l1 l2 l3
printf("%L %L %L\n" x y z)
)
printf("RC = %L\n" RC)

-> Prints the following:

1 5 9
2 6 10
RC = (1 2)

Notice that it stopped when the first list was exhausted. However, this
trick only works one way. That is it works when:

length(l1) <= length(l2) <== length(l3)

But not when:

length(l1) > length(l2) > length(l3)

HTH

 

Read the SKILL Language Reference for foreach. I believe you want to use
the second syntax form:

foreach( (a b c) list1 list2 list3
printf("%L %L %L\n" a b c)
)

Ed "Mr. Diva" Kalenda
Cadence Design Systems

This is just me blathering, not the company, since they don't let talk for them.

 

As a tcl'er I should have known ...

Thanks