how to know the coordinates of a certain alphabet$B!!(Bin a word

hi

i have a column of words that share a certain alphabet,

how to determine the coordinates of a certain alphabet so that i can

Arrange the words in a line made by the alphabet

thank you

regards

 

I'm assuming you mean they share a single letter. I would probably use
bounding boxes to break the words at the letter that is shared, and adjust
the horizontal text positions based on these widths. For example:

-- "shape" and "cactus" share "a".
-- Use GetBoundingBox() to get widths of "shape" and "cactus" text
objects.
-- Change SHAPE's textstring to APE and store the original word in a
variable.
-- Change CACTUS's textstring to ACTUS and store the original word in a
variable.
-- Use GetBoundingBox() to get widths of APE and ACTUS text objects.
-- Change the words back to their original values.
-- The new Y-coord for the CACTUS text should be found by the following
formula:
(Y-coord of insert point of SHAPE) + (width of SHAPE) - (width of APE) +
(width of CACTUS) - (width of ACTUS)

If you have a column, just go down the list of words, using this method on
each one to align it with the first word.
This isn't tested, it's just how I would go about trying to do it.

HTH,
James

 

-- The new Y-coord for the CACTUS text should be found by the following

oops... both times, I meant to say "X-coord", not "Y-coord".

 

Thanks for your advice.i would like to try.

thank you

regards
---------------------

 

Thanks for your advice.i would like to try.
Good luck. Let us know if this approach works or does not work for you, or
if you run into problems.

James

 

hi,
i tried ,and i partly succeeded.

for i found that the widths of the bounding boxes are sometimes different
though the len of two words are same.(
i dont know why)

(for exemple word1.36 bounding box width 411, word 2.56 bounding box
width 487)

thank you after all

 

youngman,

If the font used by the text items is a "proportional" font, different
letters can have different widths. So "1.36" can have a different width
than "2.56" even though they have the same number of letters. The method I
gave you should be able to handle this, because the bounding boxes are based
on the actual font used by each text item.

My VBA isn't working yet on my new computer, otherwise I would just try to
try out a quick example.

James

 

Thank you so much.

i am too busy to have a complete try .

thanks after all.

best regards