Hiring aptitude test

Discussion in 'SolidWorks' started by Dave Nay, Feb 7, 2006.

  1. Dave Nay

    Tom L Guest

    2.5. empty 3 gal bucket, and pour remaining 2 gals from 5 gal
    bucket into 3 gal bucket.
     
    Tom L, Feb 8, 2006
    #41
  2. Dave Nay

    FrankW Guest

    LOL
    Did you get and ECO signed off for that change?
     
    FrankW, Feb 8, 2006
    #42
  3. Dave Nay

    geonv Guest

    Hi Dave,

    I was once tested at an interview to draw a simple 2-cylinder part with
    an axial hole. I was given the part and told: draw this, but no
    artistic drawings (I guess the guys there had some surprises before).
    This is probabily a good idea, and you can add 2-3 more parts and ask
    them to make an assys and put them in dwg.
    The whole "project" should take about 30 min tops and will show
    knowledge of SW basics.

    Hope it works,
    G.
     
    geonv, Feb 8, 2006
    #43
  4. Dave Nay

    Ab Guest

    1. fill the 3 gal bucket
    2. dump 3 gals into the 5 gal bucket
    3. fill 3 gal bucket again
    4. fill the remainder of the 5 gal bucket from the 3 gal, leaving 1 gal
    in the 3 gal bucket
    5. dump the 5 gal bucket
    6. dump 1 remaining gal from 3 gal bucket into 5
    7. fill 3 gal, and dump into 5 gal making 4 gals
     
    Ab, Feb 8, 2006
    #44
  5. Dave Nay

    TOP Guest

    1. Fill 3 gal bkt.
    2. Empty into 5 gal bkt.
    3. Fill 3 gal bkt.
    4. Empty into 5 gal bkt till 1 gal remains
    5. Empty 5 gal bkt.
    6. Empty 3 gal bkt into 5 gal bkt
    7. Fill 3 gal bkt and go home.

    Step 7 in your solution is two steps.

    1. Fill 5 gal bkt
    2. Empty into 3 gal bkt till 2 remain
    3. Empty 3 gal bkt
    4. Empty 5 gal bkt into 3 gal bkt
    5. Fill 5 gal bkt
    6. Empty 5 gal bkt into 3 gal bkt leaving 4 gal
    7. Go back with 5 gal bkt and tell him you lost the 3 gal bkt.
     
    TOP, Feb 8, 2006
    #45
  6. Dave Nay

    FrankW Guest

    OOOOOHHH.K.
    How about: Step 1
    Sorry Dad, no time , going to the movies
     
    FrankW, Feb 8, 2006
    #46
  7. Dave Nay

    swizzle Guest

    Yes, you would see something.

    The speed of light is relative to the observer so the lights turned on in
    the vehicle would be traveling at the speed of light faster than the
    vehicle. In essence the vehicle is standing still relative to the
    headlights' light.

    The trick, is that an observer standing still on the ground watching the
    vehicle pass by would see the light passing at the speed of light and not
    2*speed of light, assuming the shock wave created by a vehicle displacing
    that much air that quickly doesn't kill the observer.

    --Scott

    Like the comedian Stephen Wright once said to an interviewer...
    If it was dark and you were in a vehicle traveling at the speed of
    light...
    would you see anything if you turned on the headlights???
    LOL
    We need a mind binder of a riddle everyday on this newsgroup!
     
    swizzle, Feb 8, 2006
    #47
  8. Dave Nay

    Pats Fan Guest

    Damn Swizzle! Thanks for the explaination!! Now where did you pick up
    that bit of information? Are you a quantum physics major? or just a
    savy internet explorer??? LOL
     
    Pats Fan, Feb 8, 2006
    #48
  9. Dave Nay

    Cliff Guest

    Only in it's own reference frame. But it could never get to the speed
    of light anyway so the question is moot.
    IIRC Phase waves can go faster than the speed of light <g>.
     
    Cliff, Feb 8, 2006
    #49
  10. Dave Nay

    swizzle Guest

    Actually, I'm a mechanical engineering major, but I did really well in my
    quantum physics class in college.

    This tidbit of info happens to be because of a skewed interest I still
    maintain in that subject matter so I happen to come across relativistic
    topics in my readings.

    --Scott

    Damn Swizzle! Thanks for the explaination!! Now where did you pick up
    that bit of information? Are you a quantum physics major? or just a
    savy internet explorer??? LOL
     
    swizzle, Feb 9, 2006
    #50
  11. Dave Nay

    Cliff Guest

    No, as you counld never go that fast.
    http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/tdil.html

    Interestingly, the intergal of the Lorentz factor becomes
    { intergal [dx/([sqrt](1 - V^2))] = arcsin (V) + A } where V is in units of C
    and A is a constant.
     
    Cliff, Feb 10, 2006
    #51
  12. Dave Nay

    Cliff Guest

    Which guy?
     
    Cliff, Feb 10, 2006
    #52
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