Equation Question

I have a sketch that contains a fully defined circle. I would like to draw
another circle, concentric with this circle, but make it larger to the next
closest 1/16 of an inch so that we can use standard drills.

Does anyone know of a way to control the diameter of the second circle to
meet my criteria by using equations or something? It will need to update
properly if the first circle ever changes also.

TIA

 

This equation should do the trick:

new_dim = INT((old_dim+1/16)*16)/16

 

Just a stab in the dark but can you just offset by 1/32"?

Matt B.

 

try this
"D2@Sketch1" = (int("D1@Sketch1"/(1/16))+1)*(1/16)

devide the number by 1/16 to figure exactly how many 1/16s it is
Then use int to round it down to the nearest integer.
Add one to make sure it is rounded up.
multiply by 1/16 for the nearest 1/16

Regards,
Corey

 

Actually what Arlin and I posted will evaluate to the next 1/16 even if you
are at an even 1/16 so .1875 would evaluate to .25
if you use this equation
"D2@Sketch1" = iif("D1@Sketch1" >
(int("D1@Sketch1")),"D1@Sketch1",(int("D1@Sketch1"/(1/16))+1)*(1/16))
..1875 will evaluate to .1875
but .1876 would evaluate to .25

Corey

 

Corey,

Both your solution and Arlin's solution are great. I could understand
Arlin's equation a little easier though. I use equations all the time, but
didn't know about the INT command. I guess I need to do some more reading
on equations.

The only problem I ran into is that no equation will update until you exit
the sketch if the referring dimension for the equation is a driven
dimension. This has nothing to do with these specific equations though. It
is like that with any equation. That is OK as long as it does update while
exiting a sketch or rebuilding.

Anyway, thank you both.

P.S. Matthew - I needed it to update to a standard 1/16 size even if the
inner hole was non-standard....

 

I use equations all the time, but didn't know about the INT command.

FYI:
The INT operator rounds a number down to the nearest integer. It is a
common operator used in VB, Excel, and other places.

Corey's equation is really the exact same thing as mine, but in a little
different form. Corey's form is really a bit more useful as if you want
to instead round up to the nearest 1/32, you just replace all 1/16s with
1/32s. Thus,

"D2@Sketch1" = (int("D1@Sketch1"/(X))+1)*(X)
where X is the amount you wish to increment by (1/16 in your case)

OKAY, done typing now...guess I just like to see myself type.

 

Thanks Arlin for that bit of info.

Maybe one day I will actually have a chance to start trying to learn VB. My
biggest problem is that I don't know where to begin...