Drawing arcs only with lengh and a tangential line given

Hi,

Is it possible to draw an with given length and a trangential line given?
So, we have
- start point,
- line which is a tangent for arc to be drawn and
- length of arc
There is no information about the radius, chord length, sweep angle etc.

If any LISP available with any body plz. help

-shyam

 

No, not without other curve information sufficient to determine the radius.

It sounds like you're recreating a parcel map. If you can't get the deed or
filed map, then work around the parcel from the other direction to determine the
endpoint of the arc. The use the Circle;3P command. selecting Tan for each of
the two tangent lines, and Endpoint of the line you think is better. Of course
this will only approximate the original.

 

shyam,

John is 100% correct and to explain it in more detail the only thing you
know about the arc
is its length.The only equation that is applicable is L=R*Theta;
Now you have L but you have two other variables that cannot be resolved.
and the start point and the tangent vector only define the position in
space.
and basically have nothing to do with the arc.

Regards Gary
www.ltfactory.com

 

If it's a property boundary, and if you can determine the other endpoint of
the arc by working around as John suggests, then you can do better than
approximating the arc. Draw a line over the tangential line, ending at the
start point of the arc, to establish the starting direction for the arc.
Then call up the Arc command and just hit Enter, and you get to drag the
tangential arc by its other endpoint, which you can then Osnap to the
location worked around from the other direction. The resultant arc might
not agree exactly with the known length, because of rounding in property
boundary descriptions, but it should be very close.
--
Kent Cooper, AIA


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