Compound Radius

Does anyone have a way to draw a compound radius. What I mean by that is a line or polyline that has two different radius in two different planes. Similar to a segment of a spiral.

 

COMPOUND CURVES

A curve that is made up of a series of successive tangent circular arcs is called a compound curve. In figure 4-40 the problem is to construct a compound curve passing through given points A, B, C, D, and E. First, connect the points by straight lines. The straight line between each pair of points constitutes the chord of the arc through the points.

Erect a perpendicular bisector from AB. Select an appropriate point 01 on the bisector as a center, and draw the arc AB. From 01, draw the radius 01B. From BC, erect a perpendicular bisector. The point of intersection 02 between this bisector and the radius 01B is the center for the arc BC. Draw the radius 02C, and erect a perpendicular bisector from CD. The point of intersection 03 of this bisector and the extension of 02C is the center for the arc CD.

To continue the curve from D to E, you must reverse the direction of curvature. Draw the radius 03D, and erect a perpendicular bisector from DE on the opposite side of the curve from those previously erected. The point of intersection of this bisector and the extension of 03D is the center of the arc DE.

Figure 4-40



HTH
--
- Jeff

[AutoCAD 2000 / 2000 LT / 2002; WINNT 4, SP 6; 1 gig RAM; Matrox Millennium AGP]
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Does anyone have a way to draw a compound radius. What I mean by that is a line or polyline that has two different radius in two different planes. Similar to a segment of a spiral.

 

 




--
- Jeff



 



[AutoCAD 2000 / 2000 LT / 2002; WINNT 4, SP 6; 1 gig RAM; Matrox Millennium AGP]
**********************************************



"Jeff" <> wrote in message news:...



COMPOUND CURVES



A curve that is made up of a series of successive tangent circular arcs is called a compound curve. In figure 4-40 the problem is to construct a compound curve passing through given points A, B, C, D, and E. First, connect the points by straight lines. The straight line between each pair of points constitutes the chord of the arc through the points.



Erect a perpendicular bisector from AB. Select an appropriate point 01 on the bisector as a center, and draw the arc AB. From 01, draw the radius 01B. From BC, erect a perpendicular bisector. The point of intersection 02 between this bisector and the radius 01B is the center for the arc BC. Draw the radius 02C, and erect a perpendicular bisector from CD. The point of intersection 03 of this bisector and the extension of 02C is the center for the arc CD. 

To continue the curve from D to E, you must reverse the direction of curvature. Draw the radius 03D, and erect a perpendicular bisector from DE on the opposite side of the curve from those previously erected. The point of intersection of this bisector and the extension of 03D is the center of the arc DE.

Figure 4-40



HTH
--
- Jeff

[AutoCAD 2000 / 2000 LT / 2002; WINNT 4, SP 6; 1 gig RAM; Matrox Millennium AGP]
**********************************************
"apina" <> wrote in message Does anyone have a way to draw a compound radius. What I mean by that is a line or polyline that has two different radius in two different planes. Similar to a segment of a spiral.