Chamfer WF2

Discussion in 'Pro/Engineer & Creo Elements/Pro' started by g.ormesher, Feb 17, 2005.

  1. g.ormesher

    g.ormesher Guest

    Hi

    Problably an easy one but here goes.

    I have a square 21mm with 3mm rounds on the corners at a depth of
    6.2mm.
    Sitting on top of the square in the middle is a circle,10mm dia, 6mm
    height.

    I want a chamfer where the circle meets the square to extent to the
    outer edges
    of the square including the rounds.

    Thanks

    Geoff

    Wildfire 2.0
     
    g.ormesher, Feb 17, 2005
    #1
  2. g.ormesher

    David Janes Guest

    Try sweeping a 45 around the outside edge of the part. The outside edge would be
    the sweep trajectory and the round boss silhouette would be a constraining entity
    in sketcher. If you can't get it to stay 'attached' to the boss or it won't go all
    the way around because of the way Pro/e splits circles, sketch past the boss
    surface and ignore the silhouette.
     
    David Janes, Feb 17, 2005
    #2
  3. g.ormesher

    dakeb Guest

    You need a variable angle chamfer, which means you need a blend.
     
    dakeb, Feb 17, 2005
    #3
  4. g.ormesher

    David Janes Guest

    Or maybe a cut rotated about a circle the size of the middle, round boss. The
    angle would be fixed and the final chamfer shape would resemble a square,
    sharpened pencil with cylindrical, not shaprened, "lead". So many interpretations
    means some ambiguity in the question.
     
    David Janes, Feb 18, 2005
    #4
  5. g.ormesher

    g.ormesher Guest

    I got it to work with a varable section sweep, using where the cylinder
    meets the square as the origin, the outer edge of the square as "chain
    1" then I created a circular datum curve halfway down the cylinder as
    "chain 2".

    I will have a go at the blend.

    Thanks

    Geoff
     
    g.ormesher, Feb 18, 2005
    #5
  6. g.ormesher

    Jeff Howard Guest

    When you try the blend, go to the Control Points tab and manually define a
    set of control points mapping each of the block's rad tangent points to a
    circle quadrant. You should end up with four triangular planar faces and
    four "conic" faces (similar to creating a developable square to round
    transition).
     
    Jeff Howard, Feb 18, 2005
    #6
  7. g.ormesher

    g.ormesher Guest

    Thanks Jeff, worked great.
     
    g.ormesher, Feb 21, 2005
    #7
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