Cgs and Cgd from the DC simulation

Discussion in 'Cadence' started by Xiaofeng Wang, Sep 28, 2003.

  1. Hi, all:

    I am trying to get the Cgs and Cgd of a transistor (the voltages of G
    D S and Bulk are known.) I ran the DC simulation and printed the
    transistor working point. I got Cgs, Csg, Cdg, Cgd, .... Some values
    are even negative.

    I am confused. Can you tell which one is the gate to source
    capacitance?

    Thanks.


    Best Regards,

    Xiaofeng
     
    Xiaofeng Wang, Sep 28, 2003
    #1
  2. Xiaofeng Wang

    Erik Wanta Guest

    Xiaofeng:
    There should be 16 transcapacitances in total, dQi/dVj where i,j can
    be S, G, D or B. If you write these transcapacitances in matrix form,
    the sum over i of dQi/dVj is zero since there's no change in the total
    charge in a device. Also, the sum of j of dQi/dVj is zero since the
    capacitance depends only on voltage difference (if all dVj change by
    delta V, dQi should be zero too). Therefore, by knowing 9 of 16
    transcapacitances, you can always figure out the rest. This
    transcapacitance model is kind of messy for hand calculation and it
    makes more sense to think of Cij = Cji for hand calculation.
     
    Erik Wanta, Sep 28, 2003
    #2
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