Are you sleeping, Mr. M. Puckett?

It's a bug?

Example:
(member 'nil '(nil nil nil nil nil))
Result : (nil nil nil nil nil)
(member (nth 2 '(nil nil nil nil nil))'(nil nil nil nil nil)))
Result : (nil nil nil nil nil)

My solution:
(defun nts (n lst )
(cond ((zerop n) lst)
(T (append (cdr lst))(nts (1- n)(cdr lst)))))

(nth 2 '(nil nil nil nil nil))
Result : nil
(nts 2 '(nil nil nil nil nil))
Result : (nil nil nil);it's right ?

Please, listing only, bcs i d't unstd engsh

 

No, it's not a bug. Member returns the list beginning with the first
instance found.
Yours works IF you want to know if the 3rd element in one list is also in
the other list beginning with the 3rd element.

Sorry, don't know another way to explain it.

 

Thanx, Jeff
But ...

 

(member (nth 2 '(nil nil nil nil nil))'(nil nil nil nil nil)))

Not a bug.

(nth 2 '(nil nil nil nil nil))
Result: nil
(member 'nil '(nil nil nil nil nil))
Result : (nil nil nil nil nil)

 

Excuse me, Tom.
It's my damn' autumnal brain bug ...
Result : (cons 'Lisparanoia (list '(too many aplomb)))
Thanx,
~'O'~